I think it's worthwhile to update this post with a bit of math and science from previous conversations.
If you're curious about the energy requirements, so let's do some math. Note that the numbers I'll be using were obtained through simple web searches.
Assumptions and notes:
The human body is made up of the following percentages, by weight:
- Subject: 200lbs (90.72kg), 5' 10" (1.78m) adult male
- Weight and surface area of the subject are the same before and after the process
- Skeletal mass of the subject is the same before and after the process
- Gut biome differences (roughly 3.9x10^13 bacteria) will not be addressed
- 1000 calories = 1 Calorie or 1 kilocalorie (kcal); food calories are measured in kcals, so that is what we'll use here
- Numbers in this document are rounded to the hundredth, but for precision, my calculations are not rounded
Peter Apell, from Chalmers University of Technology
- 60% Water (120lbs / 54.43kg)
- 23% Soft tissue (46lbs / 20.87kg)
- 15% Bone (30lbs / 13.61kg)
- 2% Bacteria (4lbs / 1.81kg)
, did studies on how much energy is required by the body for healing wounds. This is quite a bit different from a full transformation, but reasonable research to start with, I think. He calculated the body requires about 20 kiloJoules (kJ) or 4.78kcal to grow a gram of new cells. One pound is 453.59g, so the 46lbs of soft tissue that would be "healed" would draw 417,302.80kJ, or 99,737.76kcal.
46lbs x 453.59g per pound = 20,865.14g of soft tissue
20,865.14g x 4.78kcal per gram = 99,737.76kcal
Furthermore, Apell calculated that healing for "a wound" would take around 10 days. Assuming his calculations were for the same "gram" of new cells, "healing" one gram at a time in our Subject would take 208,651.40 days, or 571.65 years (not accounting for leap years). Disruption of the entire body at once would destroy the lymphatic and circulatory systems needed to transfer the necessary nutrients and oxygen, as well as carry away dead cellular material and cell waste, resulting in death. It would also halt normal operation of the heart, brain, lungs, and other organs necessary for life, again resulting in death. Even if we assume the body could be in the process of reconfiguring 20 areas of soft body tissue at any given time, the process (not including the skeleton) would still require 10,432.57 days, or 28.58 years. Daily caloric intake for reconfiguration of soft tissue is negligible, only 9.56kcal per day.
20,865.14g x 10 days per gram = 208,551.40 days
208,651.40 days ÷ 365 days per year = 571.65 years (reconfiguring 1 area at a time)
571.65 years ÷ 20 concurrent repairs = 28.58 years
208,551.40 days ÷ 20 concurrent repairs = 10,427.57 days
99,737.76kcal ÷ 10,427.57 days = 9.56kcal/day
Remember, this is in addition to the calories required by the body to maintain the day-to-day metabolism - breathing, heart rate, brain activity, and so on. And let's not forget the energy input required to rearrange the physical lattice of calcium deposits that are the skeleton.
Exact numbers on kcal requirements for healing bone fractures seem to be less readily available, but the numbers can run as high as 4000kcal per day (above and beyond the requirements for normal, everyday bodily functions) for 6-12 weeks for "multiple fractures"
while the initial fractures heal, followed by an additional 1-2000kcal per day for an additional 12-18 weeks as the now rejoined bone continues to rebuild its structural integrity, though full healing may take as long as 1 year from the initial injury.
Because the surface area of the skeletal system is approximately the same as the surface area of our 200lbs, 5' 10" individual, this means the surface area of bone is approximately 3,250in² (8,255cm²). A clean break to a 1" diameter (2.54cm) bone affects the following areas: calculating for a .08" (0.20cm) "break", the affected surface area is 0.25in² (1.60cm²) with a volume of 0.06in³ (1.01cm³).
- Area of a rectangle: l*w
- Circumference of a circle: 2πr
- Volume of a cylinder: πr²h
- Density: m ÷ v
- Note that surface area and volume measurements can not be converted from Standard to Metric by multiplying by 2.54
Circumference of the "break" = 2π(0.50") = 3.14"
External surface area of the "break" = 3.14" x 0.08" = 0.25in²
Volume of the "break" = π(0.5²)(0.08) = 0.06in³
It must be noted that bone density varies over the course of one's life, and males and females have different bone densities. Bone density can also vary within a single individual, with larger bones like those in the arms and legs being stronger and denser than bones in the fingers or the ears. As such, the following calculations are heavily approximated
. The average bone density of a healthy 30yo male is around 1.07oz/in³ (1.85g/cm³)
. Our Subject has 30lbs or 480oz (13.61kg or 13,610g) of bone. This means that for the initial 6-12 week period, healing 0.06in³ of bone requires 168,000 - 336,000kcal, followed by 126,000 - 189,000kcal (or more) for the remainder of the healing process - for a single fracture. The initial healing of the entire skeleton then requires anywhere from 1.26x10^9 to 2.51x10^9 kcal, followed by an additional 9.42x10^8 to 1.41x10^9 kcal.
Kcal for a single fracture (0.06in³ (1.01cm³)):
4,000kcal x 42 days = 168,000kcal
4,000kcal x 84 days = 336,000kcal
For further repairs:
1,500kcal x 84 days = 126,000kcal
1,500kcal x 126 days = 189,000kcal
Kcal for the entire skeleton:
Volume of the entire skeleton: 480oz ÷ 1.07oz/in³ = 448.60in³ (7,356.76cm³)
448.60in³ ÷ 0.06in³ = 7,476.67 total "fractures" to be "repaired"
7,476.67 x 168,000kcal = 1,256,074,766.36kcal
7,476.67 x 336,000kcal = 2,512,149,532.71kcal
For further repairs:
7,476.67 x 126,000kcal = 942,056,074.77kcal
7,476.67 x 189,000kcal = 1,413,084,112.15kcal
Just like soft tissue, all of these adjustments can't be made at once. Assuming five "repairs" at a time are conducted, the Subject's daily caloric intake, excluding calories required for basic functions, becomes 20,000kcal per day for the first 6-12 weeks, and 7,500kcal per day for the remaining 12-18 weeks, with total repairs (assuming 26 weeks for each "repair") lasting 3,738.32 years.
4,000kcal/day x 5 "repairs" at a time = 20,000kcal/day
1,500kcal/day x 5 "repairs" at a time = 7,500kcal/day
7,476.67 total "fractures to be "repaired" x 26 weeks/"repair" = 194,392.52 weeks
194,392.52 weeks ÷ 52 weeks/year = 3,738.32 years
Between the soft tissue and the skeleton, we're going to need a total of approximately 2.51x10^9kcal.
Average kcal requirements for initial skeletal reconfiguration:
(1,256,074,766.36kcal + 2,512,149,532.71kcal) ÷ 2 = 1,334,579,439.25kcal
Average kcal requirements for further skeletal repairs:
(942,056,074.77kcal + 1,413,084,112.15kcal) ÷ 2 = 1,177,570,093.46kcal
Total kcal requirements for soft tissue and the skeleton:
99,737.76kcal + 1,334,579,439.25kcal + 1,177,570,093.46kcal = 2,512,249,270.47kcal
I'm worried. These kinds of requirements, they're enormous. What do I mean by "enormous"? Let's say we represent these caloric values with a Twinkie. According to my calculations, it would be a Twinkie 85.23ft (25.98m) long, weighing approximately 785.08 tons.
That's a big Twinkie.